3x^3y^-12^-1/x^-4y^02^0

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Solution for 3x^3y^-12^-1/x^-4y^02^0 equation: 


D( x )

x = 0

x^-4 = 0

x = 0

x = 0

x^-4 = 0

x^-4 = 0

1*x^-4 = 0 // : 1

x^-4 = 0

x należy do O

x in (-oo:0) U (0:+oo)

((3*x^3*y^((-12)^-1))/(x^-4))*y^(2^0) = 0

((3*x^3*y^((-12)^-1))/(x^-4))*y = 0

3*x^7*y^(11/12) = 0 // : 3*y^(11/12)

x^7 = 0

x = 0

x in { 0} 

x belongs to the empty set

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